The SN74LVT162244ADLR device from Texas Instruments is a high-performance integrated circuit designed to provide high-speed buffering and driving capabilities with 3-state outputs. This 16-bit buffer/driver is a member of the LVT family, which is characterized by its low-voltage operation and high-speed performance.
Key Features
- Technology: The device is fabricated using the advanced BiCMOS technology, which combines the high-speed performance of bipolar transistors with the low-power consumption of CMOS technology.
- Voltage Range: It operates at a nominal voltage of 3.3V, making it ideal for interfacing with low-voltage logic devices without the need for level shifting.
- Drive Capability: The SN74LVT162244ADLR offers a robust drive capability, providing high-current outputs (±24-mA) to drive heavy loads or to drive multiple lines in bus-structured applications.
- 3-State Outputs: With its 3-state outputs, the device can be placed in a high-impedance state, allowing the outputs to effectively disconnect from the circuit, which is essential for bus-oriented systems.
- Speed: This component is designed for high-speed operation, with fast propagation delays that are crucial for time-sensitive digital circuits.
- Package: The SN74LVT162244ADLR is available in a 48-pin SSOP (Shrink Small-Outline Package) that is space-efficient and suitable for surface-mount technology (SMT).
Applications
The SN74LVT162244ADLR is versatile and can be used in a variety of applications, including:
- Bus interface or bus extension applications
- Memory driving
- Data path drivers
- Backplane driving
- Signal buffering in high-speed systems
Quality and Reliability
Texas Instruments is known for its commitment to quality and reliability. The SN74LVT162244ADLR is no exception, as it is designed to meet or exceed the stringent requirements of the commercial and industrial standards. With its robust design and proven technology, this device is an excellent choice for designers looking for a reliable solution for their buffering and driving needs.